18x^2-108x+81=0

Solution for 18x^2-108x+81=0 equation:

18x^2-108x+81=0

a = 18; b = -108; c = +81;
Δ = b2-4ac
Δ = -1082-4·18·81
Δ = 5832
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5832}=\sqrt{2916*2}=\sqrt{2916}*\sqrt{2}=54\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-108)-54\sqrt{2}}{2*18}=\frac{108-54\sqrt{2}}{36}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-108)+54\sqrt{2}}{2*18}=\frac{108+54\sqrt{2}}{36}
$